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If Sin(θ)=-5/13

  1. Jul 8, 2012 #1
    1. The problem statement, all variables and given/known data

    If sin(θ) = -5/13, π < θ < 3π/2, find cos(θ/2)
     
  2. jcsd
  3. Jul 8, 2012 #2

    eumyang

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    Given that sin(θ) = y/r, that we're in Quadrant III, and that x2 + y2 = r2, you should be able to find x, and from that, cos(θ).

    Then use the cosine half-angle identity
    [tex]\cos \left( \frac{\theta}{2} \right) = \pm \sqrt{\frac{1 + \cos \theta}{2}}[/tex]
    to find cos(θ/2). Since π < θ < 3π/2, you know the range of values that θ/2 lie in, so that will tell you whether the square root should be positive or negative.
     
  4. Jul 8, 2012 #3

    SammyS

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    You need to show some effort before we can help you.

    Read the rules for this Forum.
     
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