If the coeffiencent of friction is F/R, what do you substitute in to find F and R?

  • Thread starter emscare
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  • #1
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work done by the applied force
work = force x distance = ? in joules

gain in potential energy of the block
mass x change in height

(work done by force - gain in potential energy) / (MG cos angle)


the mass of my block was 0.3389kg
mass x 9.81 = 3.324609

distance of 214.60 cm

veritcal height og 0.6425m

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The Attempt at a Solution

 

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  • #2
tiny-tim
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welcome to pf!

hi emscare! welcome to pf! :smile:

there seems to be something missing from the question … perhaps an initial and final velocity? :confused:

what exactly is the whole question?​
 
  • #3
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basically im trying to find the coefficient of fricition between two wooden surfaces but im struggeling with the equation :-)
 
  • #4
tiny-tim
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show us your full calculations, and then we'll see what went wrong, and we'll know how to help! :smile:
 
  • #5
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co-efficient of friction (µ) = F/R

F is work done by the applied force - gain in potential energy
R is mass x gravity x cos (angle of incline)

I calculated work done by the applied force by: force x distance where the force = mass x 9.81

I calculated gain in potential energy by mass x height of ramp

*both above are in joules

my answer should be around 1.2
 
  • #6
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what am i missing :? this is way above anything iv been taught and the formula isnt explained well on google :(
 
  • #7
tiny-tim
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what am i missing :?
erm :redface:

you haven't told us what the full question is,

and you haven't shown any of your actual calculations! :rolleyes:
 
  • #8
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working attached as picture
 

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  • #9
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the full question is what is the coeffiecent of friction between the two surfaces
 
  • #10
tiny-tim
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i don't understand :confused:
 
  • #11
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Post Question: If the coeffiencent of friction is F/R, what do you substitute in to find F and R?

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has anybody come accross this formular before?

is there another way to calculate the gain in potential energy
 
  • #12
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how do i delete this?
 

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