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If we connected the the positive plate of c1 to the negative plate of c2 and vice versa ?

  1. Sep 21, 2014 #1
    1. The problem statement, all variables and given/known data
    Q1= 200 C
    Q2=400 C


    2. Relevant equations

    Qtotal= Q1+Q2 ?

    3. The attempt at a solution

    Qtotal=Q1+Q2=400-200=200 C
    Is it possible to connect the positive plate of C1 to the negative plate of C2 and vice versa without the capacitor getting explode ?
     
  2. jcsd
  3. Sep 21, 2014 #2

    Simon Bridge

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    Yes.
     
  4. Sep 21, 2014 #3
    Thanks.
    One other question if I may ask, is those capacitors connected in parallel ?
    Can we say that V1=V2 ?
     
  5. Sep 22, 2014 #4

    Simon Bridge

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    If capacitors are in parallel with each other, then the voltage across one capacitor is also across the other one.
     
  6. Sep 22, 2014 #5
    ZxgZ7vO.png
    so as in this picture, it's possible and it's considered parallel, right?
     
  7. Sep 22, 2014 #6

    Simon Bridge

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    I'd say they were in series because a current will flow around the loop - forming a circuit.
    But you wouldn't normally be trying to find equivalent capacitances in that situation.

    In a steady-state those capacitors would be considered to be in parallel with each other.
    But that would be after the charges have rearranged. Before that, the distinction does not mean much.
     
  8. Sep 23, 2014 #7
    Right.
    We had a homework before, we had to calculate the final charge after the rearrangement.

    As I have been told, we calculate the final charge after the rearrangement then consider it to be parallel, Right ?
     
  9. Sep 23, 2014 #8

    ehild

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    It is right.

    ehild
     
  10. Sep 23, 2014 #9
    Thanks a lot Simon Bridge & ehild.
     
  11. Sep 23, 2014 #10

    Simon Bridge

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    That's right.
    In the configuration shown in the diagram, the voltages across the capacitors are not the same, because of the way the charges are arranged. After the charges have rearranged, the voltages will be the same.
     
  12. Sep 23, 2014 #11
    Thanks.
     
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