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If y=a(sin^n)x

  1. Feb 25, 2006 #1
    what is the first derivative?
  2. jcsd
  3. Feb 25, 2006 #2


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    So what do you think? What have you tried? (Have you tried anything?) And where do you get stuck?
    I'll give you a hint: You should use the chain rule to solve this problem:
    [tex]\frac{df}{dx} = \frac{df}{du} \times \frac{du}{dx}[/tex]
    Now, you have y = a sinnx, if you let u = sin x, you'll have:
    y = aun. And the chain rule states that y'x = y'u u'x. Can you go from here? :)
  4. Feb 25, 2006 #3


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    Set u(x)=sin(x) and use the chain rule of differentiation.
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