# If y=a(sin^n)x

1. Feb 25, 2006

### bill nye scienceguy!

what is the first derivative?

2. Feb 25, 2006

### VietDao29

So what do you think? What have you tried? (Have you tried anything?) And where do you get stuck?
I'll give you a hint: You should use the chain rule to solve this problem:
$$\frac{df}{dx} = \frac{df}{du} \times \frac{du}{dx}$$
Now, you have y = a sinnx, if you let u = sin x, you'll have:
y = aun. And the chain rule states that y'x = y'u u'x. Can you go from here? :)

3. Feb 25, 2006

### arildno

Set u(x)=sin(x) and use the chain rule of differentiation.