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If you have the seperable DE

  1. Sep 12, 2005 #1
    If you have the seperable DE....


    that eventually ends up

    (xdx)/(2x^2-6x+4)=dy/(y^2-1), right

    'cuz that's some integration I REALLY don't feel like doing by hand, so I don't wanna do the wrong thing
  2. jcsd
  3. Sep 12, 2005 #2

    James R

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    [tex]\frac{x}{2(x-2)(x-1)} dx= \frac{1}{y^2 -1}dy[/tex]

    Use partial fractions to do the left hand side, and a trig substitution on the right.
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