- #1

schattenjaeger

- 178

- 0

**If you have the seperable DE...**

dy/dx=[x(y^2-2)]/(2x^2-6x+4)

that eventually ends up

(xdx)/(2x^2-6x+4)=dy/(y^2-1), right

'cuz that's some integration I REALLY don't feel like doing by hand, so I don't want to do the wrong thing