I'm struggling with the concept of net work. If I had a box and was pushing it up an incline would the net work be all the forces parallel to displacement in x direction * displacement in the x direction added up, plus the displacement in the y direction * force gravity parallel to displacement in y direction. Or would I separate the net work based on whether displacement is in y and x direction. In other words is net work the total work in both directions of displacement on an incline added up OR is the net work calculated separately for x direction and y direction displacement. I ask this because I always thought that net work on an incline would be the work done in vertical direction displacement on incline as well as work done in horizontal direction, but when I solve problems that look for change in kinetic energy, change in k = net work and the only work included is in the direction of displacement. I tried to reconcile this using 1/2mv1^2+mgh1=1/2mv2^2+mgh2 But I got: 1/2mv^2=mgh Which is different from change in k=net work 1/2mv^2=Work in x direction So I guess this more three questions than one. Thank you for any help!