In other words is net work the total work in both directions of displacement on an incline added up OR is the net work calculated separately for x direction and y direction displacement.

I ask this because I always thought that net work on an incline would be the work done in vertical direction displacement on incline as well as work done in horizontal direction, but when I solve problems that look for change in kinetic energy, change in k = net work and the only work included is in the direction of displacement.

I tried to reconcile this using 1/2mv1^2+mgh1=1/2mv2^2+mgh2

But I got:

1/2mv^2=mgh

Which is different from change in k=net work

1/2mv^2=Work in x direction

So I guess this more three questions than one.

Thank you for any help!