1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Im in desperate need of help

  1. Jul 22, 2007 #1
    i have a few questions that i just cant seem to understand, if you could PLEASE help me i'd appreciate it!
    Consider the quadratic function f(x)=2x^2+4x-3
    what is the domain and range of f(x)?

    Find ALL asymptotes of the function f(x)=x^2-x-12
    * thats suppose to be over x-2

    and lastly Find the x- and y- intercepts of f(x)= x^2-x-12

    They might be SUPER easy to you guys but im just not understanding. Thanks for the time that you've looked over this.
    email me at girlsridemx2@yahoo.com

    and if at all possible write the equation of a rational function that has vertical asymptotes at x=2 and x=3 and a horizontal asymptote at y=-2

    yeah so im really lost
  2. jcsd
  3. Jul 22, 2007 #2
    1 - what makes a function discontinuous? is a quadratic equation continuous throughout? think division by 0.

    2 - if your numerator contains the highest power, what happens? what if your denominator contains the highest power? 1/x^n = 0

    3 - set it equal to 0 then factor.
    Last edited: Jul 23, 2007
  4. Jul 23, 2007 #3
    Thanks! How do i find the intervals off(x)=2x^2+4x-3 increasing intervals and the decreasing f(x) intervals?

    one more.....
    Let f(x)=a(x-h)^2+k be a quadratic function such that a>0 qne k<0. How many x- intercepts does f(x) have? im totally lost.

    If i could find out how to find the x intercept it would be great

    Find the x intercepts of the quadratic function f(x)=2(x-3)^2-4

    Thank you times 1 million for all the help your a math genius!
  5. Jul 23, 2007 #4
    so what are the asymptotes of that last problem?
    Last edited: Jul 23, 2007
  6. Jul 23, 2007 #5


    User Avatar
    Staff Emeritus
    Science Advisor

    Find the turning points, then classify whether they are maxima or minima.
    Well, an x-intercept means the graph crosses the x axis, i.e. it crosses the line y=0. So, if you set the function to zero then you should be able to find the answer.

    Use a similar method for this question.

    As an aside, please note that with homework questions, you must show your work before we can help you, and full solutions to homework type questions should never be given. See the PF guidelines here
  7. Jul 23, 2007 #6
    To find X intercepts, you set the problem equal to 0 and solve.
  8. Jul 23, 2007 #7
    what does a horizontal tangent tell you? and how can you use that information to find the maxima or minima?

    asymptotes: horizontal, how can you use the powers of your exponents to determine the horizontal asymptote; vertical, how do you even get a vertical asymptote?
    Last edited: Jul 23, 2007
  9. Jul 23, 2007 #8
    okay,,,,to find the degree of
    the leading coefficient is 9 right and the degree i though would be 3 but the girl at the math lab says that i should times the 2 and 3 to get 6 as the degree. Am i right or is the girl at the math lab right?
  10. Jul 23, 2007 #9
    ok now i'm confused as to what the problem is, and what the question is. start over!


  11. Jul 23, 2007 #10
    Okay, i have to state the degree abnd the leading coefficient of
    g(x)= x(x^2+9)^3(x-1)^2.

    I was thinking the leading coefficient was 9
    and the degree is 3, but the lady at the math lab yesterday told me i have to times the 2 and the 3 together because its in the same group......so what would the answer be for the degree of that entire problem...3 or 6?
  12. Jul 23, 2007 #11
    how does a vertical asymptote arise? when the denominator is 0 correct? so how can you write 2 and -3 in the denominator in terms of an equation to where it will equal 2 and -3. now for your numerator, what is the simplest way in Calculus to determine the horizontal asymptote? it's simply by the power of the degrees, so how can you set up your equation to where you can get y = -2.
    Last edited: Jul 23, 2007
  13. Jul 23, 2007 #12


    User Avatar
    Staff Emeritus
    Science Advisor

    Well, you should firstly recall the definitions of the two terms: the degree of the polynomial is the highest power of x that it contains. The leading coefficient is the coefficient of this term.

    So, the largest power of x of the polynomial will be obtained by multiplying the largest terms in the brackets together. What is the largest power in (x^2+9)^3? What is the largest power in (x-1)^2?

    I don't know why you're throwing in loads of different questions though!
  14. Jul 23, 2007 #13
    so she is saying that you can simply add the exponents bc the bases are the same? i fail to see how the bases are the same for this equation.

    g(x)= x(x^2+9)^3(x-1)^2

    going back to our exponent rules or whatever it's called:

    a^2 x a^3 = a^2+3

    (x^2+9)^3 x (x-1)^2 = ???

    ok nvm i read your reply wrong. she says you can multiply the power 2 from x^2+9 by it's power 3?

    anyways, read what cristo said.
    Last edited: Jul 23, 2007
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook