# Im so lost in Statics HELP!

1. Oct 29, 2007

### Fat Ryan

Im so lost in Statics :( :( HELP!

first of all i need to say that i do not go to a school that is known for its sciences. this of course means that we have crappy science teachers because our budget is very low. my teacher is horrible at explaining the material and whenever i ask him a question he does not explain the solution even remotely clear. ive tried the book but its pretty useless too (2 examples per 30-40 problems). the tutors on campus can pretty much only help with general physics so i guess this is my last hope.

1. The problem statement, all variables and given/known data
we are working on truss assemblys and i cant understand how this whole force moment thing works. the solutions that i calculate dont make sense when i try to visualize the situation.

here is one of my homework problems that i have been stuck on for a while now:

2. Relevant equations
where do i begin the calculations?
when calculating the Fy forces should i include point E or just use one at a time (D & E)?
do i need to take the moment about some point? (i tried C and D, but both didnt seem right)
can someone PLEASE give me a clear and precise explaination on how to solve problems like this?

3. The attempt at a solution
this is all i have so far and i doubt its correct:

Code (Text):
SUM Fx=0....Dx=0

SUM Md=0....4kN(6m) + 2kN(4m) - A(6m)=0
A= 5.333kN

SUM Fy=0....5.333kN - 4kN - 2kN + D = 0
D= 0.667kN
but this just doesnt make sense for D...

2. Oct 30, 2007

Hint: every node must be in the state of equilibrium.

3. Oct 30, 2007

### Fat Ryan

yeah i know that but i dont understand how you can just look at 1 node and say it must balance out. like look at node D, if you balance the forces on that youll have a certain Fy force right? well doesnt node E take part of that load too? i just dont understand how you can set each node to equalibrium without looking at the big picture. and how are you supposed to know when and when not to calculate moments?

i tried to talk to my professor today after class. i told him i just dont understand this stuff and ive run out of resources for help. he immediatly jumped on the defense and told me i need to do the homework....how am i supposed to do the homework if i dont understand the material? i tried to tell him that, but he just says "come on, this stuff is simple" like he ALWAYS says when anyone asks him a question. he really makes you feel like a dumbass and hes doing a good job. christ, what am i supposed to do to pass this damn class!?!? im so frustrated, sorry.

4. Oct 30, 2007

### SlideMan

^ That's probably the most difficult part of Statics...or Dynamics, for that matter. You have to be able to ignore the whole system and just focus on a single point. If you're able to do this, it's not such a difficult class.

You're right in thinking that outside forces affect the entire system...but if you break things down, this gets accounted for in the end. So look at each joint individually (drawing them separately always helps!) and write the equations for each joint. You'll be sick of free body diagrams by the time you're finished...but that's the main concept behind pretty much everything in the class.

5. Oct 30, 2007

### Fat Ryan

yeah thats everything weve been told to do. but for instance, on this problem. if i go and solve for the Dy then that means the forces dont act on E because Dy balances them out, but thats not true...

6. Oct 30, 2007

### PhanthomJay

You are quite right, you have made a good observation. The Fy reactions at D and E are statically indeterminate and you must examine the geometry of the members at those joints to determine them. The horizontal Fx componnets of the D and E reactions can be determined by summing moments about each support. Then it's plug and chug.

7. Oct 30, 2007

### Fat Ryan

i hate this stuff, i just want to have a job already

8. Oct 30, 2007

### SlideMan

OK...let's go over your equations. For the first one, we're summing forces in the x-direction, right? Don't forget the support reaction at E. That would give us: $$\Sigma F_{x}=D_{x}+E_{x}=0$$. Thus, $$D_{x} = -E_{x}$$

Next, it looks like you're summing the moments about D. That's the force perpendicular to a line intersecting D times the distance from point D. So, we should have $$\Sigma M_{D}=4kN(6m) + 2kN(4m) - E_{x}(3m)=0.$$ And $$E_{x} = 32/3$$. Note that the force at A is given as 4kN, so you don't need to figure this out.

Finally, you're summing forces in the y-direction. Again, don't forget the support reaction at E. So, $$\Sigma F_{y}=-4kN - 2kN + D_{y} + E_{y}$$. This really won't yield anything useful at this point, but you'll end up with $$D_{y} = 6 - E_{y}$$.

Hopefully, this makes sense. You now have the horizontal support reactions at D and E. Unfortunately, for this problem, those won't get you too far without some additional work. Turns out, you're better off ignoring the support reactions for now and solving the truss using the Method of Sections. Method of Joints will work, too...but you're looking at a little extra work. Try cutting the truss in a logical point and summing the forces at each edge point for the remaining section. You'll use the same methods we just used for the whole truss, except this time you'll be just analyzing a small section.