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Im stuck here. Help me please

  1. Sep 14, 2003 #1
    Ok bare with me...
    My Symbols are :
    ^=to the power
    X
    --= division
    Y

    Question:
    16^x times 32^2x+1
    ------------------
    8^3x-1

    = (2^4)^x times (2^5)^2x+1
    -----------------------
    (2^3)^3x-1

    = im stuck here i dont what to do, I got the fractions so that they have the same base but im new to this...I forget the other steps in conquering this question...

    My symbols aren't very good because my keyboard doesn't have them unfortunatly.
     
  2. jcsd
  3. Sep 14, 2003 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    16= 2^4 and 32= 2^5. (2^3)^(3x-1)= 2^(9x-3).

    Put those into the equation and see what happens.
     
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