- #1
footballxpaul
- 30
- 0
A sky diver weighing 180 lb falls vertically downward from an altitude of 5000ft and opens the parachute after 10 s of free fall. assume that the force of air resistance is 0.75(v) when the parachute is closed and 12(v) when the parachute is open, where the velocity v is measured in ft/s.
a) find speed of the sky diver when the parachute opens
b) find the distance fallen before the parachute opens
c)What is the limiting velocity V_L after the parachute opens?
d) Determine how long the sky diver is in the air after the parachute opens
I have tried to set it up like -
(dv/dt)= (.75(v))/180-a and seperating and solving but answer doesn't make sense
and
V=32(t)-(.75v/180)t that didnt make sense either
I know I am probably setting this up wrong, I was just trying to do F=ma for the set up? please point me in the right direction. Thanks!
a) find speed of the sky diver when the parachute opens
b) find the distance fallen before the parachute opens
c)What is the limiting velocity V_L after the parachute opens?
d) Determine how long the sky diver is in the air after the parachute opens
I have tried to set it up like -
(dv/dt)= (.75(v))/180-a and seperating and solving but answer doesn't make sense
and
V=32(t)-(.75v/180)t that didnt make sense either
I know I am probably setting this up wrong, I was just trying to do F=ma for the set up? please point me in the right direction. Thanks!