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I'm wondering about the solution (Electrodynamics)
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[QUOTE="Another, post: 6049847, member: 620718"] [ATTACH=full]230119[/ATTACH] [ATTACH=full]230120[/ATTACH] [ATTACH=full]230121[/ATTACH] [ATTACH=full]230122[/ATTACH] Total flux is Φ = NΦ[SUB]s[/SUB] where ## N = nl## and Φ[SUB]s[/SUB] is flux due to single loop.In problem 7.24 He solved the problem by using defined of the total flux. Why problem 7.15 He does not solve the problem with using by using defined of the total flux. such as (my solution) Φ = (nl)Φ[SUB]s[/SUB] = (nl)Bπs[SUP]2[/SUP] = μ[SUB]0[/SUB]n[SUP]2[/SUP]lπs[SUP]2[/SUP]I(t) and use ∫E⋅dl = -## (dΦ)/(dt) ## [/QUOTE]
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I'm wondering about the solution (Electrodynamics)
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