# Image charges

1. Jun 10, 2013

### adamp121

Hi,

I'm trying to use image charges to find the force that apply on the following particle (on the attachment) , but it seems that I do something wrong -
$F=2q^2/(2a^2)-2cos(60)q^2/a^2$
The gray section have 0 potential, so I've tried to put image charges like it is in the second attachment file.
Can someone help me?

Thanks,
Adam

#### Attached Files:

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• ###### temp2.jpg
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2. Jun 10, 2013

### StarsRuler

Graphics can help. But you must descript all the letters significance.¡¡¡ We are physics, not engineerings

3. Jun 10, 2013

### adamp121

Sorry...
The upper and the lower charges are negative while the two middles are positive.

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