1. The problem statement, all variables and given/known data A man holds a double-sided spherical mirror so that he is looking directly into its convex surface, 44.8 cm from his face. The magnification of the image of his face is +0.22. What will be the image distance when he reverses the mirror (looking into its concave surface), maintaining the same distance between the mirror and his face? 2. Relevant equations m = -di/do 1/f = 1/di + 1/do 3. The attempt at a solution First I solved for the focal length like this: di = - (m*do) di = - (.22*44.8) = -9.856 cm 1/f = 1/di + 1/do 1/f = 1/-9.856 + 1/44.8 f = -12.64 cm Then I tried to solve for the image height of the concave side: 1/di = 1/f - 1/do 1/di = 1/-12.64 - 1/40.8 di = -9.856 cm But the answer should have been 17.6, I don't really know what to do. Please help?