- #1

- 2

- 0

I know that i= the sq root of -1, and that i^2=-1, but i'm not sure how to approach this problem.

sq.rt.(-x^2-4x-3)

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter TKDKicker89
- Start date

- #1

- 2

- 0

I know that i= the sq root of -1, and that i^2=-1, but i'm not sure how to approach this problem.

sq.rt.(-x^2-4x-3)

- #2

- 258

- 1

i would start by factoring out the -1 and seeing if i can't factor the polynomial more.

- #3

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

TKDKicker89 said:

I know that i= the sq root of -1, and that i^2=-1, but i'm not sure how to approach this problem.

sq.rt.(-x^2-4x-3)

Exactly what

Any time you have something like this, involving a square root,even if it doesn't involve i, think about completing the square.

-x

-(x+2)

[tex]\sqrt{1-(x+2)^2}[/tex]. I don't see much more that can be done and I don't see that it has directly to do with i. Even though the original -x

- #4

- 258

- 1

[tex]\sqrt{1-(x+2)^2}[/tex] can be simplified more

- #5

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

- #6

- 87

- 0

or even [tex]\sqrt{(-1-x)(3+x)}[/tex]

Share: