We want to image carbon C14 atoms using NMR with magnetic field of B=3 T. What frequency do we need to use? Use the following facts: C14 has 0% abundance, nuclear spin of I=3 and g=0.273
The frequency is given by f= (2⋅I) ⋅ (g ⋅B ⋅μ)/(1836 ⋅h), where μ is the Bohr magneton and h is the Planck constant.
The Attempt at a Solution
Of course, there is no problem to determine the frequency f by plugging in all the relevant constants into the formula above. I have a question regarding the information of '0% abundance', because I do not know how it effects the outcome. In class we determined the analogous situation for carbon C13, which has an abundance of 1.1 %. We just used the formula above and ignored the abundance completely. But I could not find anything regarding the NMR of Carbon C14. Is it maybe possible that C14 is not detectable by NMR, due to the 0% abundance?
I would very much appreciate your help! [/B]