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Supose I drop a body of 7 Kg from a height of 2 meters. Is the impact energy equal to:

E = m * g * h = 7 * 9.81 * 2 = 137,34 Joules ?

And if it is, is the kinetic energy equal to this ammount?

Kind regards,

Kepler

- Thread starter kepler
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- #1

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- 0

Supose I drop a body of 7 Kg from a height of 2 meters. Is the impact energy equal to:

E = m * g * h = 7 * 9.81 * 2 = 137,34 Joules ?

And if it is, is the kinetic energy equal to this ammount?

Kind regards,

Kepler

- #2

Doc Al

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- #3

Gokul43201

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So, the answer to the first question is: Yes, that's pretty close to the impact energy.

Note : The above is the definition of impact energy for an event. The standard definition of impact energy, however, is for a material. In that context, the impact energy is defined as the total strain energy absorbed until fracture (but that's not relevant to this specific problem).

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