- #1

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I know:

F =

__m[delta]v__

.......[delta]t

and

F = mg , where g= -9.8 N/kg

But what is the

**?**

__impact force__Is it F =

__m[delta]v__+ mg ?

.............[delta]t

- Thread starter gonefishing
- Start date

- #1

- 2

- 0

I know:

F =

.......[delta]t

and

F = mg , where g= -9.8 N/kg

But what is the

Is it F =

.............[delta]t

- #2

- 7

- 0

[tex] F = \frac{d\rho}{dt} [/tex]

(Does my LaTeX work?)

- #3

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The ball is being dropped vertically, so do we add the weight force to dp/dt?

- #4

PhanthomJay

Science Advisor

Homework Helper

Gold Member

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When you calculate the momentum change over time, you are calculating the NET force acting on the object, per Newton's 2nd law. The net force is a combination of the gravity force downward and the normal force upward. So, what does that tell you about the 'impact' (normal) force?

The ball is being dropped vertically, so do we add the weight force to dp/dt?

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