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Impedance and Current

  1. May 30, 2014 #1
    I have solved it (:
    1. The problem statement, all variables and given/known data
    Ir=Impedance of a resistor = 330
    Ic=Impedance of a capacitor=318
    V= Sinusoidal Voltage = 240 V (RMS) is applied across the series combination.
    calculate the resulting current.

    2. Relevant equations
    Not sure

    3. The attempt at a solution
    I am really not sure how I would work out the resulting current.
    Answer
    I = 250/sqrt(330^2+318^2)
     
    Last edited: May 30, 2014
  2. jcsd
  3. May 31, 2014 #2

    Simon Bridge

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    Well done.
    Please help others by explaining how you got the answer.
     
  4. May 31, 2014 #3

    rude man

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    Should be 240/sqrt(330^2 + 318^2).
    Also, you have determined the magnitude of the current but not its phase.
     
  5. May 31, 2014 #4
    yes, sorry it's supposed to be 240 not 250. I am not sure what its phase is
     
  6. May 31, 2014 #5

    rude man

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    Gonna take a shot at it?
     
  7. May 31, 2014 #6
    Will do tomorrow
     
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