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Impedance and frequency-domain

  1. Jan 24, 2007 #1
    1. The problem statement, all variables and given/known data
    This is a general question regarding impedance in circuit analysis.
    I know that in order to find the total impedance of a circuit, you transform each element characteristic into the frequency domain, i.e.,
    [tex] R\rightarrow Z_R = R[/tex],
    [tex] C\rightarrow Z_C = \frac{1}{Cs} [/tex],
    [tex] L\rightarrow Z_L = Ls [/tex].

    And then sum up the quantities properly to get an equivalent impedance.

    My question is, what happens if you transform this quantity back using an inverse transform? Do you get a real resistance value?
     
  2. jcsd
  3. Jan 24, 2007 #2
    This transformation doesn't have an inverse for the imaginary part, since the effect of capacitor and inductance cancel out each other....

    The resistance value is the real part of the impedance... ie Re(Z) = R,
     
  4. Jan 24, 2007 #3
    what if its a circuit consisting of only a resistor and a capacitor?
     
  5. Jan 24, 2007 #4

    mjsd

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    Homework Helper

    well, why would you expect that in general you get just a purely resistive circuit when you started with a circuit with a resistor, a capacitor and an inductor?

    The property of the circuit won't change just because you have tranformed into a more convenient domain (the freq domain in this case) for calculation purposes and then changed it back. If you begin with a 1 ohms and a 2 ohms resistor, then you can say ok, the total R is 3 ohms, so I can replace them with just one 3 ohms resistor. But that's all you have really done in finding the equivalent resistance.

    same applies in the case with capacitors and inductors included. you started with R , C, L. Since C and L make up the imagary part (in freq domain) they have a chance to cancel (fully or partially). If they cancel each other fully, then you will end up having just an R in your equivalent circuit. Now if they don't cancel fully you will have either one L or one C (of different value) left pending on the phase of the equivalent resistance in freq domain.
     
  6. Jan 24, 2007 #5

    SGT

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    In the time domain you can only calculate the impedance of the circuit for specific frequencies. At the resonant frequency, you have a pure resistance, below or over the resonant frequency, you have complex impedances, either RC or LC.
    If you have a closed circuit, with sources and/or initial conditions, you can solve the resulting differential equation and have a frequency independent solution.
     
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