# Impedance - Current phasor

1. Jun 8, 2010

Impedance -- Current phasor

In a series circuit of two elements, the voltage and current, for w = 2000 rad/s, are V = 150|-45° and I = 4,74|-116,6°.That variation in the frequency of the source would result in a phasor current of 6 amps? Assuming an unlimited variation in the frequency, what is the maximum possible value for the current?

The answer is 23.6% reduction in f
And the maximum 15 amps

My attempt:

Z = V/I = 31,6|71,6° = 9,97 + 30i
Xl = 30
wL = 30
L = 0,015 and f = 318Hz

For I = 6 amps I assumed I' = 6|-116,6
Z' = V/I' = 25|71,6° = 7,89 + 23,72i
Xl = 23,72
2pif'L = 23,72
f' = 252 Hz

I find f' reduction 20,76% is correct ? How I find the maximum value for the current ?

2. Jun 8, 2010

### vela

Staff Emeritus
Re: Impedance -- Current phasor

Your mistake is in assuming the phase of the 6-amp current is the same as the previous phase. As the frequency changes, the phase of the impedance changes, so the phase relationship of the voltage and current will change.

You have an RL circuit, so the impedance is given by Z=R+iωL. At the new frequency ω', you should have Z'=R+iω'L. Note that the real part of the impedance doesn't change between the two cases; only the imaginary part does.

3. Jun 8, 2010

Re: Impedance -- Current phasor

To find w' I need z'. How calculate z' ?

4. Jun 8, 2010

### vela

Staff Emeritus
Re: Impedance -- Current phasor

Try solving for the magnitude of Z'. Since you know the real part, you can find the imaginary part and solve for ω.

5. Jun 8, 2010

Re: Impedance -- Current phasor

Xl = sqrt(25^2 - 9,97^2)
Xl = 22,93
w' = 1528,67 and f' = 243,3 (23,6% reduction)
Thanks

How I find maximum possible value for the current ?

6. Jun 9, 2010

### cartonn30gel

Re: Impedance -- Current phasor

Think about how the magnitude of impedance changes in time. Does it stay constant? Does it have a minimum or a maximum? What should it be to yield the maximum value for the current?

7. Jun 9, 2010