(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 1170 resistor, a 1.46 μF capacitor, and

a 2.7 H inductor are connected in series across

a 350 Hz AC source for which the maximum

voltage is 230 V.

Calculate the impedance of the circuit.

2. Relevant equations

Z=sqrt(R^2+(XL-XC)^20

XL=2*pi*f*L

XC=1 / (2*pi*f*C)

3. The attempt at a solution

XL= 2*pi*(350Hz)*(2.7H) = 5937.61

XC= 1 / (2*pi*350Hz* 1.46e-6 F) = .000245

Z= sqrt( 1170^2 + (5937.61 - 2.54e-4)^2) = 6051.79 ohms => 6.05179 kiloohms

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# Homework Help: Impedance homework problem

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