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Impedance homework problem

  1. Oct 22, 2008 #1
    1. The problem statement, all variables and given/known data
    A 1170 resistor, a 1.46 μF capacitor, and
    a 2.7 H inductor are connected in series across
    a 350 Hz AC source for which the maximum
    voltage is 230 V.
    Calculate the impedance of the circuit.


    2. Relevant equations

    Z=sqrt(R^2+(XL-XC)^20

    XL=2*pi*f*L

    XC=1 / (2*pi*f*C)

    3. The attempt at a solution

    XL= 2*pi*(350Hz)*(2.7H) = 5937.61

    XC= 1 / (2*pi*350Hz* 1.46e-6 F) = .000245

    Z= sqrt( 1170^2 + (5937.61 - 2.54e-4)^2) = 6051.79 ohms => 6.05179 kiloohms
     
  2. jcsd
  3. Oct 22, 2008 #2

    berkeman

    User Avatar

    Staff: Mentor

    Re: impedance

    Your Xc calculation looks wrong... should be up closer to 100 Ohms or so...
     
  4. Oct 22, 2008 #3
    Re: impedance

    awesome! thanks!
     
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