to find the the total impedance of a circuit i use 1/Zt=1/Z+1/Z...ect. this way is quite lenghty when dealing with more than two impedances.(adsbygoogle = window.adsbygoogle || []).push({});

i wonder if there is a qicker way of doing it maybe by just using the magnitude of the capacitor to get rid of the imaginary part.

for example if i had a risistor , a capacitor. and a inductor in series with a risistor.

what i did was find the impedances of each branch then used the eq ZT=(Z1.Z2)/Z1+Z2 to find the impedance of the first to branch then simpify the circuit replacing the two branches with a single impedance and used the eq again.

but it doesn't seem to agree with my lecture's answer.

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# Impedances parallel

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