to find the the total impedance of a circuit i use 1/Zt=1/Z+1/Z...ect. this way is quite lenghty when dealing with more than two impedances. i wonder if there is a qicker way of doing it maybe by just using the magnitude of the capacitor to get rid of the imaginary part. for example if i had a risistor , a capacitor. and a inductor in series with a risistor. what i did was find the impedances of each branch then used the eq ZT=(Z1.Z2)/Z1+Z2 to find the impedance of the first to branch then simpify the circuit replacing the two branches with a single impedance and used the eq again. but it doesn't seem to agree with my lecture's answer.