Impedence matching

  • Thread starter Beautucker
  • Start date

Beautucker

[SOLVED] impedence matching

I am having some trouble deriving a proof that the max power deliveredto the load is arrived at when load resistance = output resistance. Can anyone help?
 
ok, I think it was going like this....

the source has a voltage of Us, and an internal resistance of Rs. The load has a resistance of Rl.
the voltage on the load is Ul = Us(Rl/(Rs+Rl))
the power delivered to the load is P = Ul2/Rl = (Us2*Rl)/(Rs+Rl)2
if you want to know the maximum power delivered to the load you have to do dP/dRl = 0 and that yields (if I did it correctly)
dp/dRl = (Us2*(Rs-Rl))/(Rs+Rl)3
so for this to be 0 means that Rs = Rl
 

Related Threads for: Impedence matching

Replies
0
Views
2K
Replies
2
Views
2K
Replies
4
Views
3K
  • Posted
Replies
9
Views
1K
  • Posted
Replies
1
Views
1K
  • Posted
Replies
7
Views
3K
  • Posted
Replies
3
Views
2K

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top