- #1

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Help needed please.

I found the derivative of the first equation is:

sin xy + xy cos xy +4x. It's close to the answer, but not it.

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- Thread starter superdave
- Start date

- #1

- 150

- 3

Help needed please.

I found the derivative of the first equation is:

sin xy + xy cos xy +4x. It's close to the answer, but not it.

- #2

James R

Science Advisor

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[tex]= \sin xy + x (\cos xy \times \frac{d}{dx} xy) + 4x[/tex]

[tex]= \sin xy + x (\cos xy \times (x \frac{dy}{dx} + y)) + 4x[/tex]

[tex]= \sin xy + x \cos xy (xy' + y) + 4x[/tex]

[tex]= \sin xy + xy \cos xy + y'x^2 \cos xy + 4x[/tex]

- #3

HallsofIvy

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superdave said:

Help needed please.

I found the derivative of the first equation is:

sin xy + xy cos xy +4x. It's close to the answer, but not it.

In the first place x sin(xy)+ 2x

[tex]\frac{dy^2}{dx}= \frac{dy^2}{dy}\frac{dy}{dx}= 2y\frac{dy}{dx}[/tex]

or just 2y y'. What is the derivative of sin(xy) with respect to x, remembering that y is an unknown function of y?

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