i am working on a homework assignment. it's easy, or, so i think....(adsbygoogle = window.adsbygoogle || []).push({});

Given.

[tex] 3x^2 - xy^3 + sin(x^3 - y) = 4 [/tex]

Find [tex] \frac{dy}{dx} [/tex]

not a problem. i ended up with

[tex] \frac{dy}{dx} = \frac {6x - y^3 + 3x^2 cos(x^3 - y)}{3xy^2 + cos(x^3 - y)} [/tex]

using implicit differention.

now, "What is the slope of the curve defined by the equation at the point [tex] (0, \pi) [/tex]?"

at first, i plugged it into the derivative, ended up with [tex] \pi^3 [/tex], but, upon inspection, i noticed that the point [tex] (0, \pi) [/tex] does not exist in the original equation. am I to find the slope of the curve of the derivative, or is this a typo, or am i looking at this problem incorrectly? thanks.

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# Implicit diff (2 var), error or what?

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