Doing fine until I reached a trig function where I know i've done the work correctly but the answer does not match up exactly with the one in the back of the book.(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\sin(x^2y^2)=x[/tex]

I do the work using product and chain rule

[tex]\cos(x^2y^2)(2xy^2+2x^2yy')=1[/tex]

[tex]2xy^2+2x^2yy' = \frac {1} {\cos(x^2y^2)}[/tex]

[tex]y'=\frac {2xy^2} {2x^2y\cos(x^2y^2)}[/tex]

But the answer in the back of the book says

[tex]\frac {1-2xy^2\cos(x^2y^2)} {2x^2y\cos(x^2y^2)}[/tex]

Is there a theorem i'm missing?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Implicit Differentiation issue

**Physics Forums | Science Articles, Homework Help, Discussion**