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Implicit Differentiation

  1. Jul 13, 2003 #1
    Hi. I'm taking a Calculus course right now and I simply cannot understand Implicit Differentiation or the Related Rate problems. My text book does not do a good job explaining it. It is a very accelerated class and I cannot get it and I need to know it in two days for a mid term.

    I just don't understand the concept.. or well any of it.

    Could someone explain it to me?

    Thank you in advance.
  2. jcsd
  3. Jul 13, 2003 #2


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    Forget you're doing something "fancy" and just apply the rules of differentiation... remembering that if you're differentiating with respect to, say, x, the other variables are functions of x.


    xy = 1

    rememebr that y is a function of x, so write as:

    x y(x) = 1

    then differentiate both sides using the product rule

    y(x) + x y'(x) = 1

    and now if you want something interesting like y'(1), you just have an ordinary algebra problem... you have two unknowns, y(1) and y'(1), and two equations.
  4. Jul 13, 2003 #3


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    here is a good site for example to help you. visual calculus I find it easier to use the power rule for finding Dx after you have all variables to one side = 0.
    Dx :wink:
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