Implicit differentiation

  • Thread starter la_med12
  • Start date
  • #1
4
0
1.
I'm pretty sure I've got this right.. just needing a check. Cheers!

2.
x^2+2xy-y^2+x^2=2

3.
2x+2x(dy/dx)+2y-2y(dy/dx)+2x=0
2x(dy/dx)-2y(dy/dx)=-4x-2y
dy/dx(2x-2y)=-4x-2y
dy/dx=(-4x-2y)/(2x-2y)
 

Answers and Replies

  • #2
Correct, but you can factorise and multiply top and bottom by -1 to become
[tex]\frac{dy}{dx} = \frac{y+2x}{y-x} [/tex]
which looks nicer. :smile:
 
Last edited:
  • #3
4
0
Thanks for the check.

Cheers!
 

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