- #1

- 11

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## Homework Statement

**find the d^2y/dx^2 if y^3 + y = 2 cos x at the point (0,1)**

## Homework Equations

## The Attempt at a Solution

my dy/dx = (-2 sin x)/(3y^2 + 1)

I don't know how to find d^2y/dx^2?

And when and how will I use the oint (0,1)?

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- Thread starter athamz
- Start date

- #1

- 11

- 0

my dy/dx = (-2 sin x)/(3y^2 + 1)

I don't know how to find d^2y/dx^2?

And when and how will I use the oint (0,1)?

- #2

ehild

Homework Helper

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ehild

- #3

- 11

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oh.. so I have..

3y^2 * y' + y' = -2 sin x

y'(3y^2 + 1) = -2 sin x

y' = (-2 sin x)/(3y^2 + 1)

Right?

3y^2 * y' + y' = -2 sin x

y'(3y^2 + 1) = -2 sin x

y' = (-2 sin x)/(3y^2 + 1)

Right?

- #4

ehild

Homework Helper

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ehild

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