1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Implicit differentiation

  1. Oct 23, 2012 #1
    Equation: eysinx=x+xy

    I took the derivative of both sides.
    For the side with eysinx, I used the product rule and chain rule to get: ey*cosx + ey*sinx*y'
    For the side with x+xy, I used the sum and product rule to get 1+y+xy'

    So my resulting equation is: ey*cosx + ey*sinx*y'=1+y+xy', which I don't know how to solve and is probably wrong.
  2. jcsd
  3. Oct 23, 2012 #2


    User Avatar
    Science Advisor

    Why would you not knowhow to solve that for y'? If the problem were A+ By'= C+ Dy', could you solve for y'?
  4. Oct 23, 2012 #3


    User Avatar

    express y' as a function of x and y
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook