# Implicit differentiation

Equation: eysinx=x+xy

I took the derivative of both sides.
For the side with eysinx, I used the product rule and chain rule to get: ey*cosx + ey*sinx*y'
For the side with x+xy, I used the sum and product rule to get 1+y+xy'

So my resulting equation is: ey*cosx + ey*sinx*y'=1+y+xy', which I don't know how to solve and is probably wrong.