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Implicit differentiation

  1. Oct 23, 2012 #1
    Equation: eysinx=x+xy

    I took the derivative of both sides.
    For the side with eysinx, I used the product rule and chain rule to get: ey*cosx + ey*sinx*y'
    For the side with x+xy, I used the sum and product rule to get 1+y+xy'

    So my resulting equation is: ey*cosx + ey*sinx*y'=1+y+xy', which I don't know how to solve and is probably wrong.
     
  2. jcsd
  3. Oct 23, 2012 #2

    HallsofIvy

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    Staff Emeritus
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    Why would you not knowhow to solve that for y'? If the problem were A+ By'= C+ Dy', could you solve for y'?
     
  4. Oct 23, 2012 #3

    ldm

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    express y' as a function of x and y
     
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