- #1

- 12

- 0

^{y}sinx=x+xy

I took the derivative of both sides.

For the side with e

^{y}sinx, I used the product rule and chain rule to get: e

^{y}*cosx + e

^{y}*sinx*y'

For the side with x+xy, I used the sum and product rule to get 1+y+xy'

So my resulting equation is: e

^{y}*cosx + e

^{y}*sinx*y'=1+y+xy', which I don't know how to solve and is probably wrong.