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- Thread starter Sebastian B
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Mark44

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No. What you wrote above doesn't mean what you think.I unfortunately keep on getting the wrong answer to this problem.

I am supposed to find: dw/dy(1/(w^2+x^2)+1/(w^2+y^2))

I believe what you are supposed to do is use implicit differentiation to find ##\frac{\partial w}{\partial y}##, although that is not clear from what you wrote on the first line. On the third line you have a mistake. Since ##\frac{1}{w^2 + x^2}## does not involve y, its partial derivative with respect to y is zero.

Sebastian B said:I attached a picture of how I tried to solve it. Help would be much appreciated.

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RUber

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SammyS

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You mean that you need to find ∂w/∂y given that (1/(wI unfortunately keep on getting the wrong answer to this problem.

I am supposed to find: dw/dy(1/(w^2+x^2)+1/(w^2+y^2))

Hello Sebastian B. Welcome to PF !I attached a picture of how I tried to solve it. Help would be much appreciated.

In your third equation, you need to have parentheses around ##\displaystyle \ \left( 2w\frac{\partial w}{\partial y}+2y \right) \ ## .

After that the algebra is messed up.

Don't forget; the right side of the equation is zero at that point.

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Sebastian B

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No. What you wrote above doesn't mean what you think.

I believe what you are supposed to do is use implicit differentiation to find ##\frac{\partial w}{\partial y}##, although that is not clear from what you wrote on the first line. On the third line you have a mistake. Since ##\frac{1}{w^2 + x^2}## does not involve y, its partial derivative with respect to y is zero.

Mark 44: Thank you for your feedback. I realized that I wasn't clear enough with stating my problem, but you figured out what I meant. However,

\[\delta\]w/\[\delta\]y (w^2+x^2) does not equal zero, because w could be dependent on y

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Sebastian B

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