- #1

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I am given the equation [tex] (x^3 y^4)^5 = x-y [/tex]

my derivative is [tex] 1/ (15x^2 20y^3(x^3y^4)^4)=y' [/tex]

But the book says: [tex] y'=(1-15x^14y^20)/(1+20x^15y^19)[/tex]

Where did I go wrong?

Thanks so much

Chris

- Thread starter compute_a_nerd
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- #1

- 14

- 0

I am given the equation [tex] (x^3 y^4)^5 = x-y [/tex]

my derivative is [tex] 1/ (15x^2 20y^3(x^3y^4)^4)=y' [/tex]

But the book says: [tex] y'=(1-15x^14y^20)/(1+20x^15y^19)[/tex]

Where did I go wrong?

Thanks so much

Chris

- #2

Tide

Science Advisor

Homework Helper

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You didn't differentiate the left side correctly. Try again.

- #3

Fermat

Homework Helper

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You need to put curly brackets aroundcompute_a_nerd said:...

But the book says: [tex] y'=(1-15x^14y^20)/(1+20x^15y^19)[/tex]

...

Chris

[tex] y'=(1-15x^{14}y^{20})/(1+20x^{15}y^{19})[/tex]

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