- #1

- 14

- 0

I am given the equation [tex] (x^3 y^4)^5 = x-y [/tex]

my derivative is [tex] 1/ (15x^2 20y^3(x^3y^4)^4)=y' [/tex]

But the book says: [tex] y'=(1-15x^14y^20)/(1+20x^15y^19)[/tex]

Where did I go wrong?

Thanks so much

Chris

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter compute_a_nerd
- Start date

- #1

- 14

- 0

I am given the equation [tex] (x^3 y^4)^5 = x-y [/tex]

my derivative is [tex] 1/ (15x^2 20y^3(x^3y^4)^4)=y' [/tex]

But the book says: [tex] y'=(1-15x^14y^20)/(1+20x^15y^19)[/tex]

Where did I go wrong?

Thanks so much

Chris

- #2

Tide

Science Advisor

Homework Helper

- 3,089

- 0

You didn't differentiate the left side correctly. Try again.

- #3

Fermat

Homework Helper

- 872

- 1

You need to put curly brackets aroundcompute_a_nerd said:...

But the book says: [tex] y'=(1-15x^14y^20)/(1+20x^15y^19)[/tex]

...

Chris

[tex] y'=(1-15x^{14}y^{20})/(1+20x^{15}y^{19})[/tex]

Share: