1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Implicit differetiation

  1. May 24, 2012 #1
    1. The problem statement, all variables and given/known data

    find dy/dx if x=1/1 + t and y = t2/1 + t


    2. Relevant equations

    dy/dx = (dy/dt) / (dx/dt)

    3. The attempt at a solution

    dx/dt = 1 * (1 + t )^-1

    dx/dt = -1/ (1 +t)^2

    dy/dt = t^2 * (1 +t)^-1

    dy/dt = -2t/(1+ t)^2

    therfore dy/dx = -2t/(1 + t)^2 / -1/(1 + t)^2

    2t
     
  2. jcsd
  3. May 24, 2012 #2

    sharks

    User Avatar
    Gold Member

    Your equations aren't clear. Edit your post to fix them or just attach a picture/screenshot.

    x=1/1 + t meaning x= 1 +t ? or x= 1/ (1+t) ? (hence the importance of using parentheses!)

    y = t2/1 + t

    dy/dt = t^2 * (1 +t)^-1 ? So, y = t^2/1 + t ?
     
  4. May 24, 2012 #3

    jedishrfu

    Staff: Mentor

    look at dy/dt again its not just 2 t/ (1+t) there's a term missing assuming that y=t^2 /(1+t)
     
  5. May 24, 2012 #4

    Mark44

    Staff: Mentor

    Aside from the missing parentheses that have already been mentioned, you are showing equations that are incorrect. The first and third equations above are x and y, respectively, not dx/dt and dy/dt.

    In calculating dy/dt, you need to use either the product rule (on t2(1 + t)-1) or the quotient rule (on t2/(1 + t) ).
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Implicit differetiation
  1. Differetiate this? (Replies: 3)

Loading...