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## Homework Statement

If x^2+3y^2+2y = 10; dx/dt = 2, x=3 and y = -1 find dy/dt

## The Attempt at a Solution

d/dt[x^2+3y^2+2y] = d/dt[10]

3x^2 (dx/dt) + 6y(dy/dt) + 2 (dy/dt) = 0

6y (dy/dt) + 2 (dy/dt) = -3x^2 (dx/dt)

dy/dt (6y+2) = -3x^2 (dx/dt)

dy/dt = -3x^2 (dx/dt) / 6x+2

dy /dt = -3(3^2)(2) / 6(3)+2 = 13.5