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Implicit Partial Derivative

  1. Mar 6, 2016 #1

    njo

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    1. The problem statement, all variables and given/known data
    ∂z/∂x of ycos(xz)+(4xy)-2z^2x^3=5x


    2. Relevant equations
    n/a

    3. The attempt at a solution
    ∂z/∂x=(5+yz-4y+6z^2x^2)/(-yxsin(xz)-4zx^3)


    Is this correct? Just trying to make sure that's the correct answer. I appreciate the help. I can post my work if need be. Thanks
     
  2. jcsd
  3. Mar 6, 2016 #2

    LCKurtz

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    Close, but check your work. There is at least a sine term missing in the numerator. Better yet, show your work.
     
  4. Mar 6, 2016 #3

    njo

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    -y*sin(xz)*(z+x(∂z/∂x))+4y-4zx^3(∂z/∂x)-6z^2x^2 = 5

    This is what I have before rearranging and factoring for ∂z/∂x
     
  5. Mar 6, 2016 #4

    LCKurtz

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    That looks good. If you carefully do the algebra solving for ##\frac{\partial z}{\partial x}## you should be OK.
     
  6. Mar 6, 2016 #5

    njo

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    (5+yzsin(xz)-4y+6z^2x^2)/(-yxsin(xz)-4zx^3) = ∂z/∂x

    Pretty sure this is right. Just messed up on my algebra. Thank you so much. The internet is great.
     
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