# Impossible problem?

1. Nov 1, 2009

### I'm

1. The problem statement, all variables and given/known data

is( X^2 )y + (Y^2)x = 6, then the second derivative at the point (1,3) is ?

2. Relevant equations

3. The attempt at a solution

I don't see how this is possible, when I plug in 1 and 3 it comes out as 9 = 6 which isn't true. Can someone tell me if this is wrong? or if the problem is written badly?

2. Nov 1, 2009

### lanedance

fair point, but i get 12

( X^2 )y + (Y^2)x = (1)3 = (3^2)1 = 12
are you maybe missing a factor of 2?

3. Nov 1, 2009

### I'm

you're right its 12 but how can I solve the problem?

4. Nov 2, 2009

### temaire

Have you tried solving for the second derivative first?

5. Nov 2, 2009

### lanedance

well as you point out, (1,3) is not a point on the curve defined by
(x^2)y + (y^2)x = 6, so you can't really

can you write the exact question?

6. Nov 2, 2009

### I'm

Thats the equation I was given.

7. Nov 2, 2009

### lanedance

it may help if you write the whole question verbatim

but as already said, (1,3) is not a point on the curve defined by (x^2)y + (y^2)x = 6, so the question does not make sense - it is undefined