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Impossible Reflection Problem

  1. Oct 12, 2015 #1
    1. The problem statement, all variables and given/known data
    The focal length between a person and his mirror that produces a magnification of 1.50 when his face is 12.0 cm away is 0.36 m. He then moves to a distance of 3.7 times the focal length away from her mirror. What is the magnification now?

    2. Relevant equations
    di/do=m
    1/f=1/di+1/do

    3. The attempt at a solution
    I've been trying to work this out on paper for the last hour. When his distance is 2.6 times the focal length, the magnification is -0.62. I can't figure out why that is though. There seems to be 2 variables.
     
  2. jcsd
  3. Oct 12, 2015 #2

    ehild

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    The images can be real and virtual. One image is upside down, which one? What is the sign of magnification in case of a real image and in case of a virtual image?
     
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