- #1

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I'm not sure if I'm setting it up right, but so far I have that 1/rad(1+x^6) is less than or equal to x/rad(1+x^6) which is less than 1/rad(x^6).

I don't know if this is right, or where to go from here if it is right.

Thanks for your help!

- Thread starter mpgcbball
- Start date

- #1

- 11

- 0

I'm not sure if I'm setting it up right, but so far I have that 1/rad(1+x^6) is less than or equal to x/rad(1+x^6) which is less than 1/rad(x^6).

I don't know if this is right, or where to go from here if it is right.

Thanks for your help!

- #2

Dick

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- #3

Gib Z

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[tex]\frac{x}{\sqrt{x^6+1}}<\frac{x}{\sqrt{x^6}}[/tex]

For every value of x within our bounds of integration, that is true.

[tex]\int^{\infty}_1 \frac{x}{\sqrt{x^6+1}} dx< \int^{\infty}_1 \frac{1}{x^2} dx[/tex]. Since we know, and can show, the 2nd part converges, the 1st part does as well.

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