# Improper integral question

• MHB
• ozgunozgur
In summary, an improper integral is an integral with either infinite limits of integration or an unbounded integrand within the interval of integration. A proper integral, on the other hand, has finite limits of integration and a bounded integrand. An integral can be determined as improper if it meets any of the following conditions: infinite interval of integration, unbounded integrand, or a discontinuity within the interval of integration. The two types of improper integrals are type 1 and type 2, with type 1 having infinite limits of integration and type 2 having an unbounded integrand or discontinuity within the interval of integration. To evaluate an improper integral, one can use the limit definition, split the integral, or use a comparison test

#### ozgunozgur

This is my method, could you help me to continue?

note ...

$\dfrac{x\sqrt{x}}{x^2-1} > \dfrac{1}{\sqrt{x}}$

and $\displaystyle \int_2^\infty \dfrac{dx}{\sqrt{x}}$ is divergent.