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Improper integral question

  1. Jan 24, 2008 #1
  2. jcsd
  3. Jan 24, 2008 #2

    HallsofIvy

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    Your limit is wrong. xln x- x goes to 0 as x goes to 0, not infinity. Rewrite it as xlnx- x= x(ln x- 1)= (ln x-1)/(1/x) and use L'Hopital's rule.
     
  4. Jan 24, 2008 #3
    thanks
     
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