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transgalactic
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i added my question and how i tried to solve it
in the link
http://img208.imageshack.us/my.php?image=img8214ew9.jpg
in the link
http://img208.imageshack.us/my.php?image=img8214ew9.jpg
Last edited:
You switched your limits while substituting. Do it again using 1 to infinity.transgalactic said:where is my mistake in they way I've solved??
i my way didnt even came to the limit part
i was told to use limit for the interval that has infinity in it
An improper integral is an integral where one or both of the limits of integration are infinite, or the function being integrated is undefined at some point within the integration interval. This type of integral is typically used to evaluate integrals that do not have a finite answer using traditional methods.
To evaluate an improper integral, you must first determine if it is convergent or divergent. If it is convergent, you can use various mathematical techniques such as the comparison test or the limit comparison test to evaluate it. If it is divergent, it does not have a finite answer.
A convergent improper integral has a finite value, meaning that it can be evaluated using traditional methods. A divergent improper integral does not have a finite value and cannot be evaluated using traditional methods.
Yes, an improper integral can have both limits of integration as infinite. This is known as a double improper integral and is evaluated using similar techniques as a single improper integral.
Improper integrals are commonly used in physics and engineering to solve problems involving infinite quantities, such as calculating the center of mass of an object or finding the work done by a variable force. They are also used in probability and statistics to calculate the probability of events with infinite outcomes.