- #1
Nusc
- 760
- 2
Int[(x^3)/((e^x)-1)] [0, infinity]
What is the trick?
I thought of by-parts but how would you integrate 1/((e^x)-1)?
Substitution won't work with
u = e^x -1
with x = ln|u+1|
or it would be rather tough to evaluate u^3
Someone please give me a hint.
What is the trick?
I thought of by-parts but how would you integrate 1/((e^x)-1)?
Substitution won't work with
u = e^x -1
with x = ln|u+1|
or it would be rather tough to evaluate u^3
Someone please give me a hint.