# Improper integral

1. Feb 21, 2008

### ggcheck

I used u substitution to get to this point:

$$\lim_{R\rightarrow\ 3-}} \int_{-3}^{R-3} (\frac{u + 3}{sqrt{u}}) du$$

is the only way to proceed from here using integration by parts?

Last edited: Feb 21, 2008
2. Feb 21, 2008

### sutupidmath

If your calculations are correct up to this point, i do not think you need to use integ by parts. Simply just try to rearrange the integrand like this

(u+3)/u^1/2= u/u^1/2 +3/u^1/2 = u^1-1/2 +3u^-1/2 and i guess you will be fine!!!!

3. Feb 21, 2008

### ggcheck

ahhh, I didn't think to break up the fraction, for some reason I missed that

thanks :)