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Improper Integral

  1. Nov 21, 2008 #1
    1. Let F(x)= [tex]\int^{x}_{0} \frac{sint}{t}[/tex] and f(x) = [tex]\frac{sinx}{x}[/tex]. If x approaches infinity, F(x) approaches [tex]\pi/2[/tex]. So, Explain what does this mean for the improper integral [tex]\int^{\infty}_{o}\frac{sinx}{x} [/tex]

    2. Relevant equations
    Explain what does this mean for the improper integral [tex]\int^{\infty}_{o}\frac{sinx}{x} [/tex]

    3. The attempt at a solution
  2. jcsd
  3. Nov 21, 2008 #2


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    What is the definition of
    [tex]\int_a^\infty f(x) dx[/itex]?
  4. Nov 21, 2008 #3
    So im guessing that [tex]\int^{\infty}_{o}\frac{sinx}{x} [/tex] converges to pi/2?. The question seems straight forward but my teacher isn't that forgiving, im thknking theres more to it?
  5. Nov 21, 2008 #4
    Is there any reason why you called the integrand function f? You never used that definiiton in the sequel. Are you sure you copied the question correctly? As it stands it really looks somewhat like senseless:smile:
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