Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Improper Integral

  1. Sep 5, 2009 #1
    Is there any way to integrate
    [tex]\int dx/(xlogx)[/tex]

    within the limits 1 and n?

    If yes what is the result?
     
  2. jcsd
  3. Sep 5, 2009 #2
    Assuming that log x means ln x (if not a constant is just introduced), if you make the substitution u= ln x the integrand simplifies to du/u. However the limits are 0 to ln n, and so ln u would have to be evaluated at 0, which means the integral does not converge.
     
  4. Sep 5, 2009 #3
    Yes the integral doesn not converge . This can be seen without integrating - the function 1 / (x * ln x) goes to infinity at x = 1 , and also func is continous in the interval .. so the area under the curve is infinite
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Improper Integral
  1. Improper integral (Replies: 1)

  2. Improper Integration (Replies: 5)

  3. Improper integrals (Replies: 4)

  4. Improper Integrals (Replies: 1)

  5. "Improper" Integral (Replies: 3)

Loading...