1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Improper integral

  1. Feb 27, 2012 #1
    Is ∫eiωtdω = √(2[itex]\pi[/itex]) (from -∞ to ∞)

    It should be so if my books derivation of the fourier transform is correct, but they don't really explain why the above equality is correct?

    can anyone show me how they get to that result for that integral or does anyone perhaps have a good link?
     
  2. jcsd
  3. Feb 27, 2012 #2
    If you set I = integral and multiplied by the same integral, you would have I^2. When you solve that you get 2pi but then you take the square root.

    However, isn't is supposed to be equal to \frac{1}{\sqrt{2\pi}
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Improper integral
  1. Improper Integral (Replies: 5)

  2. Improper Integrals (Replies: 3)

  3. Improper integrals (Replies: 5)

  4. Improper integrals (Replies: 2)

  5. Improper Integral (Replies: 7)

Loading...