1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Improper Integral

  1. Feb 23, 2013 #1
    1. The problem statement, all variables and given/known data

    [itex]\displaystyle \int_{1}^{\infty} 1/(x^2+ 3 \ |sin x| +2) dx [/itex]


    2. Relevant equations

    N/A


    3. The attempt at a solution

    [itex]\displaystyle \int_{1}^{\infty} 1/(x^2+ 3 \ |sin x| +2) dx =[/itex]

    [itex]\displaystyle lim_{t\rightarrow \infty} \int_{1}^{t} 1/(x^2+ 3 \ |sin x| +2) dx [/itex]

    Side Work

    [itex]\displaystyle \int 1/(x^2+ 3 \ |sin x| +2) dx [/itex]

    I have now clue how to solve this integral. It can't be simplified. U substitution doesn't work nor does a trigonometric substitution. Once I can solve the indefinite itegral I can solve the rest on my own.

    Thanks in advance.
     
  2. jcsd
  3. Feb 23, 2013 #2

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    You can't solve the indefinite integral. You just want to prove the improper integral exists. Try a comparison test.
     
  4. Feb 23, 2013 #3
    Oh ok thanks that makes since now.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Improper Integral
  1. Improper Integral (Replies: 5)

  2. Improper Integrals (Replies: 3)

  3. Improper integrals (Replies: 5)

  4. Improper integrals (Replies: 2)

  5. Improper Integral (Replies: 7)

Loading...