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Improper integral

  1. May 16, 2017 #1


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    1. The problem statement, all variables and given/known data

    2. Relevant equations
    improper integral

    3. The attempt at a solution
    Whats wrong with my calculation?
    I cannot figure it out after hours...
    Thank you very much!
  2. jcsd
  3. May 16, 2017 #2
    In the substitution, it's actually ##\frac{du}{dx}=\frac{1}{2\sqrt{x}}##.
  4. May 17, 2017 #3


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    oh yes. thank you
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