1. The problem statement, all variables and given/known data Determine whether the integral is divergent or convergent. If it is convergent, evaluate it. Integral from (1 to 8) 4/(x-3)^3 dx 2. Relevant equations 3. The attempt at a solution So firstly, i pulled out the 4 and then i set the lim as t goes to 8 from the left of the integral. From there, i applied the u sub with u=x-3 and du=dx. I then did the antiderivative of it which gives me: 4 lim (as t goes to 8 from left) integral from 1 to t (1/(-2u^2)) and then i changed the limits of integration...t=t-3 and 1=-2. but when i plugged them in and evaluated i got 0.42..which is wrong...i don't know where i'm going wrong. thanks.