Improper Integrals

  • Thread starter Mathematics07
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    Integrals
  • #1
[\The question is to evaluate the integral from 1 to infinity of ∫[(1)/(3x+1)^2] dx.


No idea how to do this can anyone help explain improper integrals please.

THE ANSWER TO THE PROBLEM IS 1/12 thought . . . .

Thanks
 

Answers and Replies

  • #2
You need to find the anti-derivative and then evaluate it the anti derivative like normal, just take the limit as the upper limit of integration goes to infinity.
 
  • #3
To find that antiderivative, just substitute ' 3x +1 = p ' and then express the whole deal in terms of ' p ' .
 

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